(x-y)(x^2+2xy+y^2)=0

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Solution for (x-y)(x^2+2xy+y^2)=0 equation: 


Simplifying
(x + -1y)(x2 + 2xy + y2) = 0

Reorder the terms:
(x + -1y)(2xy + x2 + y2) = 0

Multiply (x + -1y) * (2xy + x2 + y2)
(x(2xy + x2 + y2) + -1y * (2xy + x2 + y2)) = 0
((2xy * x + x2 * x + y2 * x) + -1y * (2xy + x2 + y2)) = 0

Reorder the terms:
((xy2 + 2x2y + x3) + -1y * (2xy + x2 + y2)) = 0
((xy2 + 2x2y + x3) + -1y * (2xy + x2 + y2)) = 0
(xy2 + 2x2y + x3 + (2xy * -1y + x2 * -1y + y2 * -1y)) = 0
(xy2 + 2x2y + x3 + (-2xy2 + -1x2y + -1y3)) = 0

Reorder the terms:
(xy2 + -2xy2 + 2x2y + -1x2y + x3 + -1y3) = 0

Combine like terms: xy2 + -2xy2 = -1xy2
(-1xy2 + 2x2y + -1x2y + x3 + -1y3) = 0

Combine like terms: 2x2y + -1x2y = 1x2y
(-1xy2 + 1x2y + x3 + -1y3) = 0

Solving
-1xy2 + 1x2y + x3 + -1y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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